Aphoton of wavelength 15 x 10^-12 m hits an electron at rest, causing the electron to move. the photon bounces off the electron at some angle θ relative to its original direction. if its new wavelength is 16 x 10^-12 m, what is θ? (a) 24° (b) 36° (c) 54° (d) 66°

c) 54°

Explanation:

let h be the planck constant, m be the mass of an electron and c be the speed of light. let λn be the new wavelength and λ be the initial wavelength. [h/(m×c)] = 2.43×10^-12 m.

then, according to compton effect:

          Δλ = [h/(m×c)]×(1 - cos(θ))

     λn - λ = [h/(m×c)]×(1 - cos(θ))

1 - cos(θ) = (λn - λ)/[h/(m×c)]

  cos(θ)  = 1 - (λn - λ)/[h/(m×c)]

   cos(θ) =  1 - (16×10^-12 - 15×10^-12)/[2.43×10^-12]

   cos(θ) = 0.5884773663

           θ = 53.95°

              ≈ 54°

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.