Physics, 07.08.2019 04:20 owlsandR5

Aproton is traveling horizontally to the right at 4.40×106 m/s .
part a
find (a)the magnitude and (b) direction of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.20 cm .
e =
nothing
n/c
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part b
? =
nothing
? counterclockwise from the left direction
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part c
how much time does it take the proton to stop after entering the field?
t =
nothing
s
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part d
what minimum field ((a)magnitude and (b)direction) would be needed to stop an electron under the conditions of part (a)?
e =
nothing
n/c
submitrequest answer
part e
? =
nothing
? counterclockwise from the left direction

Answers: 2

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Aproton is traveling horizontally to the right at 4.40×106 m/s .
part a
find (a)the magnit...