One way to keep the contents of a garage from becoming too cold on a night when a severe subfreezing temperature is forecast is to put a tub of water in the garage. if the mass of the water is 122 kg and its initial temperature is 22.7°c, how much energy must the water transfer to its surroundings in order to freeze completely? the specific heat of water is 4186 j/kg·k, and the latent heat of fusion is 333 kj/kg.

E = 5.221 × 10⁷ J

Explanation:

Given:

Mass of water, m = 122 kg

Initial temperature of the water, T₁ = 22.7°C

Specific heat of the water, Cp = 4186 J/kg.K

Latent heat of fusion, = 333 kJ/kg = 333 × 10³ J/kg

Now,

The for energy (E) by the water during freezing is as:

E = Energy released from 22.7°C to get to 0°C + energy released from 0°C to freezing

or

E = mCpΔT +

on substituting the values, we get

E = 122 × 4186 × (22.7° - 0°) + 122 × 333 × 10³

or

E = 5.221 × 10⁷ J

Hence, the total energy released by the water is 5.221 × 10⁷ J

photocells convert light energy to electricity

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.