What will the kinetic energy of a pile driver ram be if it starts from rest and undergoes a 10 kj decrease in potential energy?

Explanation:

As per mechanical energy conservation law we can say that sum of kinetic energy and potential energy will always remains constant

so here we can say

here we have

as initially it starts from rest

so now we have

now we know that its final potential energy is decreased by 10 kJ

so we have

so the final kinetic energy will be

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures