16 grams of ice at –32°c is to be changed to steam at 172°c. the entire process requires cal. round your answer to the nearest whole number. the specific heat of both ice and steam is 0.5 cal/g°c. the specific heat of water is 1.00 cal/gk. the heat of fusion is 80 cal/g and the heat of vaporization is 540 cal/g.

12,352 cal

Explanation:

Given

to change 16 gm ice at

First we need to take ice to then change its state to water and then raises water temperature from 0 to .

After it change water phase to steam and then raise its temperature to

+

Q=12,352 cal

the answer would be a

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s