Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. both the source and screen are far enough from the slit for fraunhofer diffraction to apply. a) if the first diffraction minima are at ±90.0∘, so the central maximum completely fills the screen, what is the width of the slit? b) for the width of the slit as calculated in part (a), what is the ratio of the intensity at θ=45.0∘ to the intensity at θ=0?

Aliquid is an answer i hope this

Sorry i don’t know what to do

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Answerthe valence of an element or radical is equal to the number of positive or negative charges on the ion.