Physics, 03.08.2019 06:10 leoiscoolcool

When water is boiled under a pressure of 2.00 atm, the heat of vaporization is 2.20×10^6 j/kg and the boiling point is 120 c. at this pressure, 1.00 kg of water has a volume of 1.00×10^−3 m3, and 1.00 kg of steam has a volume of 0.824 m^3.(a)compute the work done when 1.00kg of steam is formed at this temperature(b)compute the increase in internal energy of the water.

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When water is boiled under a pressure of 2.00 atm, the heat of vaporization is 2.20×10^6 j/kg and th...