Avoltage v is applied to the primary coil of a step-up transformer with a 3: 1 ratio of turns between its primary and secondary coils. a resistor r connected to the secondary dissipates a power p = 100 w. how much power is dissipated by the same resistor when the ratio of turns in the transformer is changed to 24: 1 and the same input voltage is used?

Explanation:

Let are the number of turns in primary and secondary coil of the transformer such that,

A resistor R connected to the secondary dissipates a power

For a transformer,

...............(1)

The power dissipated through the secondary coil is :

.............(2)

Let are the new number of turns in primary and secondary coil of the transformer such that,

New voltage is :

...............(3)

So, new power dissipated is

So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.