When karl kaveman adds chilled grog to his new granite mug, he removes 10.9 kj of energy from the mug. if it has a mass of 625 g and was at 25°c, what is its new temperature? specific heat capacity of granite = 0.79 j/(g·k)

3°C

Explanation:

We can that heat Q=m dT

Where m is the mass = specific heat capacity

dT = Temperature difference

here we have given m=625 g =.625 kg

specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)

=25°C

we have to find

we have also given Q=10.9 KJ

10.9=0.625×0.79×(25-)

25- =22

=3°C

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer