Steam flows steadily through an adiabatic turbine. the inlet conditions of the steam are 4 mpa, 500◦c, and 80 m/s, and the exit conditions are 30 kpa, 92% quality, and 50 m/s. the mass flow rate of the steam is 12 kg/s. (a) determine the change in kinetic energy. (b) what is the power output of the turbine? (c) determine the turbine inlet area.

a) ΔEC=-23.4kW

b)W=12106.2kW

c)

Explanation:

A)

The kinetic energy is defined as:

(vel is the velocity, to differentiate with v, specific volume).

The kinetic energy change will be: Δ ()=

Δ ()=

Where 1 and 2 subscripts mean initial and final state respectively.

Δ()=

This amount is negative because the steam is losing that energy.

B)

Consider the energy balance, with a neglective height difference: The energy that enters to the turbine (which is in the steam) is the same that goes out (which is in the steam and in the work done).

We already know the last quantity: =Δ ()=23400W

For the steam enthalpies, review the steam tables (I attach the ones that I used); according to that,

The exit state is a liquid-vapor mixture, so its enthalpy is:

Finally, the work can be obtained:

C) For the area, consider the equation of mass flow:

where is the density, and A the area. The density is the inverse of the specific volume, so

The specific volume of the inlet steam can be read also from the steam tables, and its value is: , so:

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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