The fayette power station* is a coal-fired power plant located near la grange, texas and provides electric power for both the houston and austin metro areas. this power station has a nominal output power of 1,760 mw (electric), and has an approximate thermal efficiency of 40%. heat is provided to the plant by combustion of coal, and the thermal sink for the plant is lake fayette, a manmade reservoir. using the given data, determine the rate of heat rejection to lake fayette (mw).

2640 MW

Explanation:

The Heat rejection rate is the rate at which the heat energy get lost from a system to the environment

It is obtained by finding the difference in heat supplied and the work obtained from the system

Given

Efficiency = 40% = 0.4

Power produced/output= 1760MW

The expression for heat supplied rate is ;

Qs=P/η

where P is power output and η is the efficiency

Qs=1760/0.4 =4400MW

The expression for rate of heat rejection is given by;

Qr=Qs-P

where Qr is rate of heat rejection, Qs=4400 MW and P=1760MW

Qr= Qs-P

Qr=4400-1760 = 2640MW

the part of the wave he is travelling on is the crest

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.