subject
Physics, 02.08.2019 17:20 milliebbbrown

You are designing a thin transparent reflective coating for the front surface of a sheet of glass. the index of refraction of the glass is 1.52, and when it is in use the coated glass has air on both sides. because the coating is expensive, you want to use a layer that has the minimum thickness possible, which you determine to be 104 nm. what should the index of refraction of the coating be if it must cancel 550-nm light that hits the coated surface at normal incidence?

ansver
Answers: 1

Other questions on the subject: Physics

image
Physics, 22.06.2019 11:30, slim2077
Two 1.20-m nonconducting wires meet at a right angle. one segment carries + 2.50 µc of charge distributed uniformly along its length, and the other carries - 2.50 µc distributed uniformly along it, as shown in fig. 21.50. ( a. find the magnitude and direction of the electric field these wires produce at point p, which is 60.0 cm from each wire. ( b. if an electron is released at p, what are the magnitude and direction of the net force that these wires exert on it?
Answers: 3
image
Physics, 22.06.2019 12:40, live4dramaoy0yf9
Question part points submissions used suppose that 2 j of work is needed to stretch a spring from its natural length of 26 cm to a length of 36 cm. (a) how much work is needed to stretch the spring from 28 cm to 32 cm? (round your answer to two decimal places.)
Answers: 2
image
Physics, 22.06.2019 18:30, kayleahrayne
Ablock of mass m slides on a horizontal frictionless table with an initial speed v0 . it then compresses a spring of force constant k and is brought to rest. the acceleration of gravity is 9.8 m/s2. how much is the spring compressed x from its natural length? 1) x = v0*sqrt(k/(mg)) 2) x=v0*sqrt(m/k) 3) x=v0*((mk)/g) 4) x=v0*sqrt(k/m) 5) x=v0*(m/kg) 6) x=v0*sqrt((mg)/k) 7) x=(v0)^2/(2g) 8) x=v0*(k/(mg)) 9) x=(v0)^2/(2m) 10) x=v0*((mg)/k)
Answers: 3
image
Physics, 22.06.2019 20:40, mathman783
Abasketball star covers 2.65 m horizontally in a jump to dunk the ball. his motion through space can be modeled precisely as that of a particle at his center of mass. his center of mass is at elevation 1.02 m when he leaves the floor. it reaches a maximum height of 1.90 m above the floor and is at elevation 0.910 m when he touches down again. (a) determine his time of flight (his "hang time"). (b) determine his horizontal velocity at the instant of takeoff. (c) determine his vertical velocity at the instant of takeoff. (d) determine his takeoff angle. (e) for comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations yi = 1.20 m, ymax = 2.45 m, and yf = 0.750 m.
Answers: 1
You know the right answer?
You are designing a thin transparent reflective coating for the front surface of a sheet of glass. t...

Questions in other subjects:

Konu
Mathematics, 16.10.2021 21:30