The distance at inferior conjunction (closest to earth) is calculated by subtracting the planet’s orbit size from earth’s distance from the sun (1 au). what is venus’s distance at inferior conjunction?

42 × 10⁶ km.

Explanation:

The orbital size of the planet Venus is 0.72 AU which is less than the orbital size of the Earth. This means that Venus is an inner planet. An inferior conjunction takes place when an inner planet passes between the Sun and the Earth. Venus lies at the closest distance from Earth at inferior conjunction. This is distance is about 42 × 10⁶ km.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

not too sure thinking all accelerations are pointed down