As a dilligent physics student, you carry out physics experiments at every opportunity. at this opportunity, you carry a 1.11-m-long rod as you jog at 3.17 m/s, holding the rod perpendicular to your direction of motion. what is the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an emf of 0.291 mv across the rod? express the answer in milliteslas.

Explanation:

Induced emf in a moving rod ( also called motional emf ) = BLV ( B is magnetic field , L is length of rod and V is velocity of rod.

given emf = .291 x 10V , B =? L = 1.11 m , V= 3.17 m/s

.291x 10⁻³ = B 1.11 x 3.17

B = .291 x 10⁻³/(1.11x3.17) =0.082 10⁻³ T teslas.=.082 militesla..

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2