Ions having equal charges but masses of m and 2m are accelerated through the same potential difference and then enter a uniform magnetic field perpendicular to their path. if the heavier ions follow a circular arc of radius r, what is the radius of the arc followed by the lighter?

\frac{R}{^{\sqrt{2}}}

Explanation:

q1 = q , q2 = q

m1 = M, m2 = 2M

Potential difference is V

Let v1 be the speed of first particle and v2 be the speed of second particle.

Energy due to potential difference gives the kinetic energy to the particle.

1/2 m x v^2 = e V

v^2 = 2 e V / m = 2e V / m ... (1)

Now radius is given by

r = m v / B q

by eqution (1)

For first particle

  .... (2)

For second particle

   .... (3)

Divide equation (2) by equation (3), we get

So

r1 / r2 =

im not to sure what it is

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!