An electric field of 106 n/c acts on an electron, resulting in an acceleration of 1.3 ✕ 1017 m/s2 for a short time. what is the magnitude of the radiative electric field observed at a location a distance of 4 cm away along a line perpendicular to the direction of the acceleration?

5.20535×10⁻⁸ V/m

Explanation:

ε₀ = Permittivity of space = 8.854×10⁻¹² F/m

a = Acceleration of electron = 1.3×10¹⁷ m/s²

r = Radiative distance = 4 cm = 0.04 m

c = Speed of light

q = Charge of electron = 1.6022×10⁻¹⁹ C

Radiative electric field

∴ Magnitude of the radiative electric field observed is 5.20535×10⁻⁸ V/m

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14