Two planes start from los angeles international airport and fly in opposite directions. the second plane starts 1/2 hour after the first plane, but its speed is 40 kilometers per hour faster. find the airspeed of each plane if 2 hours after the first plane departs, the planes are 3035 kilometers apart.

1. 850 km/hr

2. 890 km/hr

Explanation:

Total distance =  3035 km

Le the speed of first plane = X km/hr

    The speed of second plane = X + 40

 Now Time for first plane to reach destination = 2 hr

         Time for second plane to reach destination = 2 - 1/2

                                                                                   = 1.5 hr

        As distance = speed × time

and total distance = distance traveled by both planes

                   3035  =  2X + 1.5 ( X + 40 )

                   3035 =  3.5X + 60

                       3.5X = 2975

                            X = 850 km/hr

Therefore, speed of first plane = 850 km/hr

                  speed of second plane = 850 + 40

                                                         = 890 km/hr

that is probably false!

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j