Aburglar attempts to drag a 110 kg metal safe across a polished wood floor assume that the coefficient of static friction is 0.4, the coefficient of kinetic friction is 0.3, and that the burglar can apply a pushing force of 524 n on the metal safe. what is the acceleration of the metal safe across floor?

The acceleration of the metal safe across floor is 1.83 m/s².

The given parameters;

The weight of the metal safe is calculated as;

Fₙ = mg

Fₙ = 110 x 9.8

Fₙ = 1078 N

The frictional force on metal safe is calculated as follows;

The net horizontal force on the metal safe is calculated as follows;

The acceleration of the metal safe across floor is calculated as follows;

F = ma

Thus, the acceleration of the metal safe across floor is 1.83 m/s².

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a = 1.82 m/s/s

Explanation:

Here give that

static friction coefficient on the floor = 0.4

kinetic friction coefficient on the floor = 0.3

mass of the box = 110 kg

now the normal force on the box due to ground is given as

Now the minimum force required to move the box on the rough surface in horizontal direction is given as

now it is given that force applied by the burglar is 524 N which is more than the static friction

so here the box will have kinetic friction on it

now the net force on the box is given as

now the acceleration of the box is given by Newton's II law