Along string is moved up and down with simple harmon motion with a frequency of 42 hz. the string is 543 m long and has a total mass of 47.2 kg. the string is fixed at both ends. what is the tension in the string?

T = 6051.70 N

Explanation:

Given;

Frequency, f = 42 Hz

Length of the string, L = 543 m

Mass of the string, m = 47.2 kg

Now,

the frequency is given as:

where, T is the tension in the string

M is the mass per unit length = m/L = 47.2/543 = 0.0869

on substituting the values in the above equation, we get

or

or

T = 6051.70 N

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y