Aluminum has a coefficient of linear expansion of 2.4x10^-5 c^-1 and a coefficient of volume expansion of 7.2x10^-5 c^-1. an aluminum wire at 20 degrees c has a length of 10 m and a cross-sectional area of 1 cm^2. it is then heated to 100 degrees c. what is the new length of the wire?

New length = 10.2 m

Explanation:

Let ΔL  = change in length

     ΔT = change in the temperature

     L(0) = intial length

     α = coeffient of linear expansion

Then

ΔL = αL(0)ΔT

    =(2.4×10^-5)(10)(100-20)

    =0.0192 m

New length = L(0) + ΔL

                   = 10 + 0.0192

                   = 10.2 m