The combustion of 1 l of gasoline releases about 3.4×10^7j of energy. in one car's engine, about 80% of that energy is lost as heat. a. how much work is done by the engine for each liter of gasoline burned? (answer in mj/l)
b. if the car requires 5.9×10^5 j of work to travel 1 km, find the fuel efficiency in km/l.

A) The work done by the engine is: 6.8MJ/L

B) The fuel efficiency is

Explanation:

A)

We know that the gasoline releases about 3.4*10^7 J of energy for each liter, and about 80% of that energy is lost as heat; it means that the other 20% of the energy released is taken for the engine to do work. In that sense, the work done by the engine is 20% of the 3.4*10^7 J that the gasoline releases for 1 liter, so:

This last can be seen as a conversion factor, where we multiply the energy released by the gasoline by the factor (20 J taken for do work for each 100 J released).

B) We know that the car requires 5.9*10^5 J of work for each km traveled. That is the energy that the car requires, but it is not the energy that you have to give to the car; take in mind that the energy that you put in the car in gasoline liters will be not taken all, but just 20%. Also we know that the work done by the engine for 1 liter of gasoline is 6.8MJ, and that is just the work taken for do work (the useful energy), so we can connect both data:

The first fraction, is the ratio or the proportion of (1 km requieres 5.9*10^5 J); and we multiply by the second fraction , which is the ratio: 6.8*10^6 J of work done for each liter of gasoline.

they are non-matter

explanation:

they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate

e) none of the above answers are correct