Asoftball of mass 0.220 kg that is moving with a speed of 5.5 m/s (in the positive direction) collides head-on and elastically with another ball initially at rest. afterward the incoming softball bounces backward with a speed of 3.9 m/s. (a) calculate the velocity of the target ball after the collision. (b) calculate the mass of the target ball.

The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

Explanation:

Given that,

Mass of softball = 0.220 kg

Speed = 5.5 m/s

(a). We need to calculate the velocity of the target ball

Using conservation of momentum

....(I)

The velocity approach is equal to the separation of velocity

(b). We need to calculate the mass of the target ball

Now, Put the value of v₂ in equation (I)

Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

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c

explanation: