A0.8 m length of wire is formed into a single turn, square loop in which there is a current of 12 a. the loop is placed in magnetic field of 0.12 t, which is perpendicular to a normal to the loop plane. what is the maximum torque that the loop can experience?

0.073 N-m

Explanation:

i = 12 A, l = 0.8 m, B = 0.12 T

The circumference of the loop is 0.8 m.

Let r be the radius of the loop.

2 x 3.14 x r = 0.8

r = 0.127 m

Maximum Torque = i x A x B

Maximum Torque = 12 x 3.14 x 0.127 x 0.127 x 0.12 = 0.073 N-m

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: