A75 kg man rides on a 39 kg cart moving at a velocity of 2.3 m/s. he jumps off with zero horizontal velocity relative to the ground. what is the resulting change in the cart's velocity, including sign?

Explanation:

As we know that man and cart is taken as a system then the net force of them is zero.

So here we can apply momentum conservation for the system

So here we have

now we know that

mass of man = 75 kg

mass of cart = 39 kg

initially man and cart is moving together with speed 2.3 m/s

final speed of man with respect to ground is zero

So here we have

So change in velocity of the cart is given as

the answer would be 32*f