Four acrobats of mass 75.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. the 75.0-kg acrobat is at the bottom of the tower. (a) what is the normal force acting on the 75-kg acrobat? (b) if the area of each of the 75.0-kg acrobat’s shoes is 425 cm2 , what average pressure (not including atmo- spheric pressure) does the column of acrobats exert on the floor? (c) will the pressure be the same if a differ- ent acrobat is on the bottom?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Mass of bob (g)will be the answer

The correct answer would be d. because when a volcanoe erupts it cobers the sun with thick ashes and blocks sunlight so there would beba big decrease in solar energy