Physics, 23.07.2019 06:10 emily5400

A2.50-kg textbook is forced against a horizontal spring of negligible mass and force constant 250 n/m, compressing the spring a distance of 0.250 m. when released, the textbook slides on a horizontal tabletop with coefficient of kinetic friction \mu_kμ k = 0.30. use the work–energy theorem to find how far the text-book moves from its initial position before coming to rest.

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Answer from: AmyGonzalez1385

The distance that the textbook moves from its initial position before coming to rest is 1.0629m

According to the work-energy theorem, the work done on the spring is equal to the work done by friction

Work done by the spring = $\frac{1}{2}kx^2$

Work done by friction = $\mu mgL$

k is the spring constant = 250 N/m

x is the distance moved by the spring = 0.250m

$\mu$ is the coefficient of friction = 0.30

m is the mass of the textbook = 2.50kg

g is the acceleration due to gravity = 9.8m/s²

L is the distance from its initial position before coming to rest

Using the formula

$\frac{1}{2} kx^2=\mu mgL$

Substitute the given parameters into the formula as shown;

$\frac{1}{2} (250)(0.25)^2=0.3 (2.5)(9.8)L\\7.8125=7.35L\\L=\frac{7.8125}{7.35}\\L= 1.0629m$

Hence the distance that the textbook moves from its initial position before coming to rest is 1.0629m

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Answer from: Zaida21

L = 1.06 m

Explanation:

As per work energy theorem we know that work done by all forces must be equal to change in kinetic energy

so here we will have

$W_{spring} + W_{friction} = KE_f - KE_i$

now we know that

$W_{spring} = \frac{1}{2}kx^2$

$W_{friction} = -\mu mg L$

initial and final speed of the book is zero so initial and final kinetic energy will be zero

$\frac{1}{2}kx^2 - \mu mg L= 0 - 0$

here we know that

k = 250 N/m

x = 0.250 m

m = 2.50 kg

now plug in all data in it

$\frac{1}{2}(250)(0.250)^2 = 0.30(2.50)(9.81)L$

now we have

7.8125 = 7.3575L

L = 1.06 m

Answer from: Quest

. west

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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