Ga projectile is launched with speed v0 from point a. determine the launch angle ! which results in the maximum range r up the incline of angle " (where 0 ≤ " ≤ 90°). evaluate your results for " = 0, 30°, and 45°

The range is maximum when the angle of projection is 45 degree.

Explanation:

The formula for the horizontal range of the projectile is given by

The range should be maximum if the value of Sin2θ is maximum.

The maximum value of Sin2θ is 1.

It means 2θ = 90

θ = 45

Thus, the range is maximum when the angle of projection is 45 degree.

If the angle of projection is 0 degree

R = 0

It means the horizontal distance covered by the projectile is zero, it can move in vertical direction.

If the angle of projection is 30 degree.

R = 0.088u^2

If the angle of projection is 45 degree.

R = u^2 / g

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