Electromagnets 23. to hold fire doors open, an electromagnet is switched on, generating a magnetic field if a solenoid is 2.00 cm long, has 400 turns, carries a current of 1.90 a and its core is air, calculate the magnetic flux density inside the solenoid, in tesla

0.0478 T

Explanation:

L = 2 cm = 0.02 m, N = 400, i = 1.9 A

The magnetic field intensity due to a current carrying solenoid is given by

B = \mu _{0}ni

Where, n be the number of turns per unit length

n = N / L = 400 / 0.02 = 20,000

B = 4\pi \times 10^{-7}\times 20000\times 1.9

B = 0.0478 T

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever