Acircular loop of diameter 10 cm, carrying a current of 0.20 a, is placed inside a magnetic field b⃗ =0.30 tk^. the normal to the loop is parallel to a unit vector n^=−0.60i^−0.80j^. calculate the magnitude of the torque on the loop due to the magnetic field.

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Answerapply an acl that has all deny ace statement;

The answer is 4f======since electrostatic force is given by    we let f be the electrostatic force when  r = 1 m    if we let  denote the electrostatic force when the distance is decreased so that r = 0.5m, then    we established earlier that f = kq₁q₂. therefore    the force will now be 4f.