An airplane is attempting to land on a runway when the wind is blowing at a velocity of 10 m/s perpendicular to the runway. given that the airplane is flying at an airspeed of 47 m/s, at what angle relative to the runway direction must the pilot keep the nose pointed into the wind to maintain a flight path aligned with the runway?

The pilot must keep the tip pointed at 12.1 degrees to the right with respect to the direction of the runway to align the flight path with the runway.

Explanation:

x= -10m/s

y= 47m/s

r= √(x²)+(y²)

r=48.05 m/s

β= tan⁻¹(y/x)

β=102.01°

the runway is at 90 degrees. Considering the wind, the airplane is flying at 102.01 º direction. Must fly at 12.1 degrees to the right with respect to the direction of the runway to contrarest the wind effect.

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.