Physics, 16.07.2019 17:20 chloeboo

Arock is dropped from a height of 2.5 meters. what is its velocity when it reaches the ground?

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Answer from: 173899

The velocity of the rock when it reaches the ground is

Explanation:

The formula we are using is

=> Where

is the velocity in

=> Where

is acceleration in

=> Where

is the change in displacement in

So now we just plug in the numbers.

(

9.8

)

(

2.5

)

√

The velocity of the rock when it reaches the ground is

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

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