Suppose you exert a force of 180 n tangential to a 0.280-m-radius 75.0-kg grindstone (a solid disk). (a)what torque is exerted? (b) what is the angular acceleration assuming negligible opposing friction? (c

(a)

The torque exerted on the solid disk is given by

where

F is the magnitude of the force

r is the radius of the disk

is the angle between F and r

Here we have

F = 180 N

r = 0.280 m

(because the force is applied tangentially to the disk)

So the torque is

(b)

First of all, we need to calculate the moment of inertia of the disk, which is given by

where

m = 75.0 kg is the mass of the disk

r = 0.280 m is the radius

Substituting,

And the angular acceleration can be found by using the equivalent of Newtons' second law for rotational motions:

where

is the torque exerted

I is the moment of inertia

is the angular acceleration

Solving for , we find:

i believe the answer is a

the force on the thing and the distance the force moves the thing