Two flies land on a spinning record. one fly, a, lands at the edge of the record at distance, t. the second ty, b, lands on a spot that is at r. what is the relative speed of by b comparedvo ily a a fly b moves at the same speed as fly a. fly b moves at a speed that is ⅓ the speed of fly a. c. fly b moves at a speed that is ¼ the speed of fly a. d. fly b moves at a speed that is twice the speed of fly a. e. fly b moves at a speed that is four times the speed of fly a. ridr) a rider finds herself pressed with her bac

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.

Ithink the answer is fusion