Travelling with velocity 1) calculate the energy e (in ev) and direction vector ω for a neutron v= 2132 +3300+154 k [m/sec]. (3 points) ^ ^

Explanation:

Given:

Velocity vector

the mass of neutron, m = 1.67 × 10⁻²⁷ kg

Now,

the kinetic energy (K.E) is given as:

or

or

substituting the values in the K.E equation

or

also

1J = 6.242 × 10¹⁸ eV

thus,

Now, the direction vector

or

or

or

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.