Aheat engine receives heat from a source at 1000°c and rejects the waste heat to a sink at 50°c. if heat is supplied to this engine at a rate of 105.5 kj/s, the maximum power this heat engine can produce is

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000

the right answer is 0.3 meters per second