Aforce f is used to raise a 4-kg mass m from the ground to a height of 5 m. what is the work done by the force f? (note: sin 60° = 0.87; cos 60° = 0.50. ignore friction and the weights of the pulleys.)

196 Joules

Explanation:

Hello

Note:  I think the text in parentheses corresponds to another exercise, or this is incomplete, I will solve it with the first part of the problem

the work  is the product of a force applied to a body and the displacement of the body in the direction of this force

assuming that the force goes in the same direction of the displacement, that is upwards

W=F*D (work, force,displacement)

the force necessary to move the object will be

196 Joules

I hope it helps

where's the following? you gotta add it to know what the choices are

explanation:

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2