Acurrent density of 7.00 10-13 a/m2 exists in the atmosphere at a location where the electric field is 185 v/m. calculate the electrical conductivity of the earth's atmosphere in this region.

electrical conductivity is given as

Explanation:

For a current carrying conductor we will have relation between current density and electric field inside the conductor as

here we have

current density = j

electric field = E

given that

now we will have

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m