Determine the magnitude of the magnetic flux through the south-facing window of a house in british columbia, where earth's b⃗ field has a magnitude of 5.8×10−5t and the direction of b⃗ field is 72∘ below horizontal with the horizontal component of b⃗ field directed to the north. assume the area of the window is 4.0 m2. express your answer in tesla meter squared.

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The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)

120v is the answer i am positive tell me if this was correct