Avertically mounted spring (k = 750 n/m) is compressed by 35.0 cm relative to its unstrained length. a mass (m = 0.36 kg) is placed at rest against the spring. when the spring is released, the mass is launched vertically in the air. how high from release point the mass can reach?

The maximum height reached by the mass when the spring is released is 13.02 m.

The given parameters;

Apply the principle of conservation energy to determine the maximum height reached by the mass when the spring is released.

mgh = ¹/₂kx²

where;

Thus, the maximum height reached by the mass when the spring is released is 13.02 m.

Learn more here:link

Height, h = 13.02 meters

Explanation:

It is given that,

Spring constant of the spring, k = 750 N/m

It is compressed by 35 cm relative to its unstained length, x = 35 cm = 0.35 m

Mass of the object, m = 0.36 kg

When the spring is released, the mass is launched vertically in the air. We need to find the height attained by the mass at this position. On applying the conservation of energy as :

Energy stored in the spring = change on potential energy

h = 13.02 meters

So, the mass will reach a height of 13.02 meters. Hence, this is the required solution.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

elctricity and magnet is conversion to it