Water ice has a density of 0.91 g/cm2, so it will float in liquid water. imagine you have a cube of ice, 10 cm on a side. a. what is the cube's weight? b. what volume of liquid water must be displaced in order to support the floating cube? c. how much of the cube is under the surface of the water

(i) W = 8.918 N

(ii)

(iii) d = 9.1 cm

Explanation:

Part a)

As we know that weight of cube is given as

here we know that

now the mass of the ice cube is given as

now weight is given as

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

So here volume displaced is given as

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

so it is submerged by d = 9.1 cm inside water

it will be pushed away from the source of the electric field. a negative charge in a cloud induces a positive charge in the ground below the cloud.

explanation: