An electron is moving east in a uniform electric field of 1.55 n/c directed to the west. at point a, the velocity of the electron is 4.52×105 m/s pointed toward the east. what is the speed of the electron when it reaches point b, which is a distance of 0.395 m east of point a?

Final velocity of electron,    

Explanation:

It is given that,

Electric field, E = 1.55 N/C

Initial velocity at point A,

We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :

........(1)

a is the acceleration,

We know that electric force, F = qE

Use above equation in equation (1) as:

v = 647302.09 m/s

or

So, the final velocity of the electron when it reaches point B is . Hence, this is the required solution.

no

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