An object moving at a constant speed requires 4.0 s to go once around a circle with a diameter of 5.0 m. what is the magnitude of the instantaneous acceleration of the particle during this time? o2.20 m/s2 3.93 m/s2 6.17 m/s2 12.3m/2 15.4 m/g2

Acceleration, a = 6.17 m/s²

Explanation:

It is given that,

Diameter of the circular track, d = 5 m

Radius of circular track, r = 2.5 m

An object moving at a constant speed requires 4.0 s to go once around a circle. We need to find the instantaneous acceleration of the particle during this time. It is given by :

Where

= angular velocity

or

So, the  instantaneous acceleration of the particle during this time is 6.17 m/s². Hence, this is the required solution.

waves moving from a fast medium to a slow medium will experience a reflection as light travels more slowly than red light. total internal reflection occurs when the critical angle is.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2