Aball is thrown at an angle of 45° to the ground. if the ball lands 79 m away, what was the initial speed of the ball? (round the answer to the nearest whole number. g = 9.8 m/s2)

The initial velocity of the ball is 28 m/s.

Explanation:

Given that,

Angle = 45°

Distance = 79 m

Using formula of horizontal and vertical distance

.....(I)

.....(II)

Put the value in both equation

Now,put the value of t in equation (II)

Hence, The initial velocity of the ball is 28 m/s.

c. newton's third law of motion

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