Asquare loop of wire with 10 turns and a side length of 1 m is placed in a changing magnetic field. if the magnetic field changes from 2 t to 4 t with 8 seconds, what is the average induced emf? a) 2.5 v b) 1.25 v c) zero d) 5 v

The average induced emf is 2.5 V.

(A) is correct option.

Explanation:

Given that,

Number of turns = 10

Length of side = 1 m

change in magnetic field = 4-2=2 T

Time t = 8 sec

We need to calculate the average induced emf

Using formula of induced emf

Where,

N = number of turns

A = area of cross section

B = magnetic field

t = time

Put the value into the formula

Hence, The average induced emf is 2.5 V.

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

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