A230-newton box rests on a plank 5 meters long. one end is 1.2 meters higher than the other end. find the components of the force the box exerts

55.3 N, 223.3 N

Explanation:

First of all, we can find the angle of the inclined plane.

We have:

L = 5 m the length of the incline

h = 1.2 m is the height

We also have the relationship

where is the angle of the incline. Solving for the angle,

Now we can find the components of the weight of the box, which is the force that the box exerts on the plank. Calling W = 230 N the weight of the box, we have:

- Component parallel to the incline:

- Component perpendicular to the incline:

b) phosphorus pentoxide

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle