A4.0 kg object is moving with speed 2.0 m/s. a 1.0 kg object is moving with speed 4.0 m/s. both objects encounter the same constant braking force, and are brought to rest. which object travels the greater distance before stopping? a) the 4.0 kg object b) the 1.0 kg object c) both objects travel the same distance d) it cannot be determined from the information given.

Both objects travel the same distance.

(c) is correct option

Explanation:

Given that,

Mass of first object = 4.0 kg

Speed of first object = 2.0 m/s

Mass of second object = 1.0 kg

Speed of second object = 4.0 m/s

We need to calculate the stopping distance

For first particle

Using equation of motion

Where, v = final velocity

u = initial velocity

s = distance

Put the value in the equation

....(I)

Using newton law

Now, put the value of a in equation (I)

Now, For second object

Using equation of motion

Put the value in the equation

....(I)

Using newton law

Now, put the value of a in equation (I)

Hence, Both objects travel the same distance.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.