Ametal sphere of radius 10 cm carries a charge of +2.0 μc uniformly distributed over its surface. what is the magnitude of the electric field due to this sphere at a point 5.0 cm outside the sphere's surface? (k=1/4πϵ0=8.99×109 n · m2/c2) a metal sphere of radius cm carries a charge of μc uniformly distributed over its surface. what is the magnitude of the electric field due to this sphere at a point cm outside the sphere's surface? ( n · m2/c2) 4.0×109 n/c 4.0×107 n/c 8.0×107 n/c 4.2×106 n/c 8.0×109 n/c

The magnitude of the electric field due to this sphere at the given distance is 8 x 10⁵ N/C.

The given parameters;

The magnitude of the electric field due to this sphere at the given distance is calculated using Coulomb's law;

where;

R = (0.1 + 0.05) m = 0.15 m

Thus, the magnitude of the electric field due to this sphere at the given distance is 8 x 10⁵ N/C.

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Explanation:

Outside the sphere's surface, the electric field has the same expression of that produced by a single point charge located at the centre of the sphere.

Therefore, the magnitude of the electric field ar r = 5.0 cm from the sphere is:

where

is the Coulomb's constant

is the charge on the sphere

is the radius of the sphere

is the distance from the surface of the sphere

Substituting, we find

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.