Abullet is shot at an angle of 32° above the horizontal on a level surface. it travels in the air for 6.4 seconds before it strikes the ground 92m from the shooter. what was the maximum height reached by the bullet?

H = 4.12 m

Explanation:

As we know that horizontal range is the distance moved in horizontal direction

Since horizontal direction has no acceleration

so here we have

here we know that

so from above formula

now we have maximum height is given as

a=d/t

a="triangle"v/t

explanation:

a = acceleration