Aproton starting from rest travels through a potential of 1.0 kv and then moves into a uniform 0.040-t magnetic field. what is the radius of the proton's resulting orbit? (mproton = 1.67 × 10-27 kg, e = 1.60 × 10-19 c)

The radius of the proton orbit is 0.114m

When the proton travels through the potential V it gains kinetic energy given below:

Now, a moving charge under magnetic field B undergoes circular motion due to the magnetic force being perpendicular to the velocity of the charge, given by:

the radius of the orbit is 0.114m

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Radius = 0.11 m

Explanation:

To find the speed of the proton we know that

here we have

now we have

now we have

Now for the radius of the circular motion of charge we know

a person with a mass of 106kg has a weight of 1060n

d eras and periods