An electron follows a helical path in a uniform magnetic field of magnitude 0.340 t. the pitch of the path is 6.00 µm, and the magnitude of the magnetic force on the electron is 1.85 10-15n. what is the electron's speed?

The electron's speed is 34007.35 m/s

Explanation:

It is given that,

Magnetic field, B = 0.34 T

Magnetic force on the electron,

The electron follows a helical path. We have to find the speed of an electron. The formula for magnetic force is given by :

q = charge on an electron,

v = velocity of an electron

v = 34007.35 m/s

Hence, this is the required solution.